mitrosus

joined 2 years ago
[–] mitrosus@discuss.tchncs.de 7 points 1 year ago (4 children)

They will most likely continue to use win 10 oblivious of its EOL. I have seen many using windows 7 even now. Some tech-aware will install win11 in the same machine by registry hack or sth. Very, very few will consider the possibility of alternatives.

[–] mitrosus@discuss.tchncs.de 3 points 1 year ago

Understood. Serving emotional content is the social media stunt to grab attention. News is not The intention. And without enough context, it increases polarity in our society. Tiktok is a master of this tactic.

[–] mitrosus@discuss.tchncs.de 3 points 1 year ago

Some things last over my lifetime, and that's "lasts" enough.

[–] mitrosus@discuss.tchncs.de 2 points 1 year ago

Shows how much been biased countrywise the posts are. And internet in general.

[–] mitrosus@discuss.tchncs.de 1 points 1 year ago

You don't know bang! ? Oh, google doesn't have the feature.

[–] mitrosus@discuss.tchncs.de 4 points 1 year ago

Spot on mate! Love you. Made my day

[–] mitrosus@discuss.tchncs.de 7 points 1 year ago

Yes. Thanks. Sorry.

[–] mitrosus@discuss.tchncs.de 11 points 1 year ago

Oh I am sorry. I did not see the x sign between 3 and 7. Lol.

[–] mitrosus@discuss.tchncs.de 2 points 1 year ago (5 children)

Wrong. Two hints:

7x7=9 at the end, not 7.

30x30=900, already more than 777.

[–] mitrosus@discuss.tchncs.de 1 points 1 year ago (1 children)

In scenario 1, legit or not, you said the chance is still 50-50. In other scenarios also you shouldn't change or it wouldn't matter. That's what I say, just in the opposite direction. But the problem of probability depends on the wordings and phrases, which means I may not have understood the ques well.

Another angle: You explained the Monty Hall problem at the end that the probability changes because in second choice we have more information. So you are implying that the initial 1/3 probability of the now-open door adds to the door we did not choose - making the switch advisable. Here I also say the probability does change from initial 1/3, but to 1/2-1/2 for each remaining doors; why should the probability be poured to the unselected single door?

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