m0darn

joined 2 years ago
[–] m0darn@lemmy.ca 51 points 5 months ago (1 children)

I was told there was no such thing as a shortage in a free market, why won't the executive branch embrace free market economics?

[–] m0darn@lemmy.ca 1 points 5 months ago (1 children)

I'm torn on this.

On the one hand it's absurd to invite a leader that's waging an economic war against us, with the aim of eliminating our sovereignty.

On the other hand, we don't really belong in G7, so we'd be putting our membership in jeopardy, which would be bad for Canada's economy, autonomy and influence.

On the other other hand, it's my understanding that the G7 is a tool of capital to co ordinate advanced economies with the aim of perpetuating unjustified wealth inequality both within those countries and compared to the Global South.

So all together um, I don't know

[–] m0darn@lemmy.ca 2 points 5 months ago (1 children)

I just came across this article and thought you might be interested, though maybe it's all old hat to you.

https://www.joanwestenberg.com/american-tech-is-compromised-heres-my-replacement-stack-2/

[–] m0darn@lemmy.ca 2 points 5 months ago (4 children)

I wonder if Canadian factories/mills/mines are seeing panic buying by their American customers.

[–] m0darn@lemmy.ca 3 points 5 months ago

"Only turns to the right are compatible with Teslas"

[–] m0darn@lemmy.ca 5 points 5 months ago (3 children)

I understand that conservative movements have done an effective job at aligning our culture's concept of masculinity with conservative values.

What I don't understand is that the stat is "under 35's", not "males under 35". One would think that for every man that feels progressive politics is for triggerable-purple-haired-whales and no-good-lazy-soyboys, there would be more than one woman that feels conservative politics is for abusive-crypto-fascist-dicks and no-good-vacuous-pickmes.

Men are only half the population, so what's drawing women to conservative politics?

[–] m0darn@lemmy.ca 1 points 5 months ago (2 children)

I hadn't heard of Ralph Bakshi.

https://en.wikipedia.org/wiki/Ralph_Bakshi

He was an animated film maker and poet that operated on the fringe of what was acceptable.

He directed the 1978 Lord of the Rings animated film.

[–] m0darn@lemmy.ca 15 points 5 months ago (2 children)

As a Canadian, could it be rebranded to Western Democratic Union (or something), so we can join? Also it might help UK undo its mistake if it didn't have to admit its mistake.

[–] m0darn@lemmy.ca 4 points 5 months ago (1 children)

I think you still haven't provided enough context:

They played each other earlier in the tournament in Canada and the Canadian fans booed the US national anthem

...due to America's leader denying Canada's sovereignty, and launching a tariff regime intended to cripple Canada's economy.

In this game the Americans booed Canada's national anthem, while in a sense retaliatory is also a doubling down and refusal to acknowledge the legitimacy of Canada's grievance.

[–] m0darn@lemmy.ca 1 points 5 months ago

Okay I did the same calculation but with Martian orbit as dyson sphere size, and 50% efficiency I got a wavelength of 3.4um so nicely in the infrared range of JWST.

I think the sphere would need to be like 99.95% efficient to be undetectable by JWST at Martian orbit radius.

[–] m0darn@lemmy.ca 1 points 5 months ago* (last edited 5 months ago) (1 children)

Edit to add disclaimer: this is shitpost level math here guys, I'm just spitballing.

It would definitely emit thermal radiation. if it was 99% efficient and the size of pluto's orbit, around a star like the sun, and the energy was used to create matter, I think it would radiate the remaining energy as 0.009 W/m2 with a peak emission wavelength of 150micrometers. The James Webb telescope has infrared capabilities that max out at 28.5 micrometers so def not detectable.

But probably a dyson sphere would be smaller than pluto's orbit, which would greatly increase the apparent power, and shorten the wavelength. idk it's all imaginary.

I won't subject you to my hand writing but I did (power of sun × 0.01)/(surface area of sphere with Pluto's orbital radius) to get radiation intensity (0.009 W/m2). Then rearranged Stefan-Boltzmann law to solve for temperature (19.8K). Then used Wien's Displacement Law to calculate the peak wavelength (1.5×10^-4^ m).

Maybe I'll run the numbers again with a martian orbit radius, and 50% efficiency.

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