this post was submitted on 20 Apr 2024
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Yep. A vertical line segment above A with length ๐ is a horizontal line segment to the left that's 1 unit long. So, the diagram needs a "not to scale" caveat like a map projection, but there's nothing actually wrong with it, and the triangle's BC side is 0 units long.
i= โ(-1) = imaginary number (1^2) + (โ(-1))^2 = 1 - 1 = 0 7
At least, I thought that was the idea in the OP.
Also, for your version, on a number line or Cartesian plane, the distance from -1 to 1 is 2, not 0
Yeah. I cheated. You have to either deliberately misunderstand how to measure vectors or else drop a minus sign for it to work my way.
(Or, from my previous example, you could just frame it as you're getting the hypotenuse by measuring between |AB| and -|AC|๐ instead of the way I framed it -- but that makes it more obvious that you're fishing for a particular answer.)
I liked your other reply better, but either way I still have more to learn. ie, I had no idea what the complex plane is.