To reduce the chance of errors, you can multiply all numbers by a factor of 10, 100, 1000, 10000, .... for the timeout. The higher the factor, the lower the chances of an incorrect result. And as no one asked about performance...

[–] BlueKey@fedia.io 3 points 7 hours ago

Maybe not peak performance but heigh CPU efficency, it's load ist mostly 0.

[–] filcuk@lemmy.zip 35 points 16 hours ago (1 children)

As added benefit, you can then opyimise the code by dividing the number by 2, making it twice as fast. Think of the savings!

[–] lugal@lemmy.dbzer0.com 5 points 11 hours ago

Better yet: take the square root and you get a sub-linear run time