this post was submitted on 14 Jul 2025
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[–] marcos@lemmy.world 8 points 2 weeks ago (6 children)

Hum... I don't think the integral "operator" applies by multiplication.

You can put the dx at the beginning of the integral, but not before it.

[–] OrganicMustard@lemmy.world 1 points 2 weeks ago (3 children)

If you were using nonstandard analysis with dx an infinitesimal you could put it outside I guess. Maybe with differential forms too?

[–] marcos@lemmy.world 2 points 2 weeks ago (1 children)

Switch it with a summation operator and see if it makes sense. The problem isn't the operation by itself, but the fact that the operator implies an argument application, like a function.

[–] OrganicMustard@lemmy.world 1 points 2 weeks ago

In the case of dx as an infinitesimal it makes sense. You are making a sum of all the values of the function in the integral range and multiplying with a constant dx.

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